Scope Resolution Operator In C++

Scope Resolution Operator In C++ How To Best Utilize Scope Resolution Operator In C++? 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Scope resolution operator in C++ can be used for:Accessing a global variable when there is a local variable with same nameDefining a function outside a classAccessing a classs static variablesReferring to a class inside another classI n case of multiple InheritanceNamespaceNow lets understand each of the purpose one by one with the help of examples.Accessing a global variable when there is a local variable with same nameYou can use scope resolution operator to access the global variable if you have a local variable with the same name. In the below example we have two variables both name num with global local scope. So, to access the global num variable in the main class you need to use scope resolution operator (i.e. ::num).Example #includeiostream using namespace std; int num = 30; // Initializing a global variable num int main() { int num = 10; // Initializing the local variable num cout Value of global num is ::num; cout nValue of local num is num; return 0; } OutputMoving on with this article on Scope Resolution Operator In C++Defining a Function Outside a ClassIf you are declaring a function in a class and then later want to define it outside the class, you can do that using scope resolution operator. In the below example, we are declaring a function Speed in Class Bike. Later we are defining the function in the main class using scope resolution operator.Example #includeiostream using namespace std; class Bike { public: // Just the Function Declaration void Speed(); }; // Defining the Speed function outside Bike class using :: void Bike::Speed() { cout Speed of Bike is 90 KMPH; } int main() { Bike bike; bike.Speed(); return 0; } OutputMoving on with this article on Scope Resolution Operator In C++Accessing a classs static variablesYou can access the classs static variable using class name scope resolution operator (i.e. class_name::static_variable). You can see in the below example, we are declaring a static variable in the class. We are defining the variable outside the class using the scope resolution operator. Then we are accessing it using class name scope resolution operator.Example #includeiostream using namespace std; class Try { static int num1; public: static int num2; // Local parameter hides class member // Class member can be accessed it using :: void function(int num1) { // num1 static variable can be accessed using :: // inspite of local variable num1 cout Static num1: Try::num1; cout nLocal num1: num1; } }; // Defining a static members explicitly using :: int Try::num1 = 10; int Try::num2 = 15; int main() { Try o; int num1 = 20 ; o.function(num1); cout nTry::num2 = Try::num2; return 0; } OutputMoving on with this article on Scope Resolution Operator In C++Referring to a class inside another classYou can create nested class with same variable names in both the classes. You can access both the variables using scope resolution operator. For the inner class variable, you need to use Outer_Class::Inner_Class::variable. Example #includeiostream using namespace std; class Outside_class { public: int num; class Inside_class { public: int num; static int x; }; }; int Outside_class::Inside_class::x = 5; int main(){ Outside_class A; Outside_class::Inside_class B; } Moving on with this article on Scope Resolution Operator In C++In case of multiple InheritanceIf you have two parent classes with same variable names and you are inheriting both of them in the child class, then you can use scope resolution operator with the class name to access the individual variables.In the below example, we are creating two parent class Parent1 Parent2, and both of them have variable num. When we are inheriting both of them in Child class, we can access both the num variables using class name scope resolution operator.Example #includeiostream using namespace std; class Parent1 { protected: int num; public: Parent1() { num = 100; } }; class Parent2 { protected: int num; public: Parent2() { num = 200; } }; class Child: public Parent1, public Parent2 { public: void function() { cout Parent1's num is Parent1::num; cout nParent2's num is Parent2::num; } }; int main() { Child obj; obj.function(); return 0; } OutputMoving on with this article on Scope Resolution Operator In C++NamespaceSuppose we have two namespaces both contains class with same name. So to avoid any conflict we can use namespace name with the scope resolution operator. In the below example we are using std::cout.Example #includeiostream int main(){ std::cout Hello std::endl; } OutputNow after going through the above programs you would have understood everything about scope resolution operator in C++. I hope this blog is informative and added value to you.Now after executing the above program you would have understood the Scope Resolution Operator In C++. Thus we have come to an end of this article on Quicksort in Java. If you wish to learn more, check out the Java Training by Edureka, a trusted online learning company. Edurekas Java J2EE and SOA training and certification course is designed to train you for both core and advanced Java concepts along with various Java frameworks like Hibernate Spring.Got a question for us? Please mention it in the comments section of this blog and we will get back to you as soon as possible.Recommended blogs for you Your Guide to the Top 10 IT Certifications for 2020 Read Article How do you make a Career in Software Testing? Read Article How to Choose the Right Postgraduate Program for You? Read Article What are the top 10 features of C++? 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